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Khan academy product rule calculus
Khan academy product rule calculus












khan academy product rule calculus

You'll take the derivative of the other one, but not the first one. Them, but not the other one, and then the other one In each of them, you're going to take the derivative of one of So the way you remember it is, you have these two things here, you're going to end up So times v of x and then we have plus the first expression, not its derivative, just the first expression. Not the derivative of it, just the second expression. So I could write that as u prime of x times just the second expression This is going to beĮqual to the derivative of the first expression. This is going to be equal to, and I'm color-coding it so we can really keep track of things. So if we take theĭerivative with respect to x of the first expression in terms of x, so this is, we couldĬall this u of x times another expression that involves x. And let me just write down the product rule generally first. But, how do we find theĭerivative of their product? Well as you can imagine, Respect to x of cosine of x is equal to negative sine of x.

Khan academy product rule calculus how to#

We know how to find theĭerivative cosine of x.

khan academy product rule calculus

So when you look at this you might say, "well, I know how to find "the derivative with e to the x," that's infact just e to the x.

khan academy product rule calculus

And like always, pause this video and give it a go on your own before we work through it. So let's see if we can find the derivative with respect to x, with either x times the cosine of x.














Khan academy product rule calculus